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(1.5x^2)-3x-80=0
We add all the numbers together, and all the variables
-3x+(1.5x^2)-80=0
We get rid of parentheses
1.5x^2-3x-80=0
a = 1.5; b = -3; c = -80;
Δ = b2-4ac
Δ = -32-4·1.5·(-80)
Δ = 489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{489}}{2*1.5}=\frac{3-\sqrt{489}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{489}}{2*1.5}=\frac{3+\sqrt{489}}{3} $
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